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Re: UnitStep


Because you are asking it to evaluate 0/0. Instead of a replacement Rule, use

Simplify[(1/p) UnitStep[p-1], p<1]

0

Limit[(1/p) UnitStep[p-1], p->0]

0


Bob Hanlon

> 
> From: "Blimbaum, Jerry AA R22" <jerry.blimbaum at navy.mil>
To: mathgroup at smc.vnet.net
> Date: 2004/11/23 Tue AM 02:12:45 EST
> To: mathgroup at smc.vnet.net
> Subject: [mg52338] [mg52326] UnitStep
> 
> Why does the following give me 'indeterminate, infinite expression
> encountered', etc. instead of  zero....
> 
> 
> (1/p) UnitStep[p-1] /.p->0
> 
> 
> I defined a function using the UnitStep because p could  = 0  and I
> thought this would be the way around that problem.......but didnt work
> the way I expected.....
> 
> 
> jerry blimbaum
> 
> 
> 


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