derivatives in cylindrical coords??

*To*: mathgroup at smc.vnet.net*Subject*: [mg51260] derivatives in cylindrical coords??*From*: "news" <anonym at bamboo.com>*Date*: Sun, 10 Oct 2004 05:52:34 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

are derivative rules different for cylindrical coordinates?? for example, taking derivative of unit vectors in Cartesian coords with base units vector {x, y, z} gives: d/dx {x, 0, 0} = {1, 0, 0} d/dy {0, y, 0} = {0, 1, 0} d/dz {0, 0, z} = {0, 0, 1} now, for cylindrical coords where base vectors are: {r, phi, z}, does this hold?? d/dr {r, 0, 0} = {1, 0, 0} d/dphi {0, phi, 0} = {0, 1, 0} d/dz {0, 0, z} = {0, 0, 1} I'm finding that it doesn't work , becuase if you cross d/dr with d/dphi in cylindrical coords, you get {0,0,0}, and you should get {0,0,1}, so something is missing in this derivative process, no??? Can anyone help??