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Re: plotting groups of polynomial roots

  • To: mathgroup at
  • Subject: [mg51285] Re: plotting groups of polynomial roots
  • From: Roger Bagula <tftn at>
  • Date: Tue, 12 Oct 2004 01:57:48 -0400 (EDT)
  • References: <ckajb5$m4j$> <ckd674$52u$>
  • Reply-to: tftn at
  • Sender: owner-wri-mathgroup at

This idea was inspired by the w cummutator of Potter matrix groups:
( in this month's Math Monthly journal)
When A and B are unitary matrices it suggests
the root group:
They are an interesting group of polynomials.
The de Moivre relationship is:
So the relationship to the unit circle isn't unexpected,
but it is nice.
The other roots are what makes the result interesting.
If nothing else it is a new way to look at Pascal's triangle.
Narasimham G.L. wrote:

>Roger Bagula <tftn at> wrote in message news:<ckajb5$m4j$1 at>...
>>If you take the first and last term away from a binomial polynomial and 
>>set the result equal to zero,
>>you get a number of strange roots.
>>This method allows you to plot such roots.
>>I didn't know it would work when I wrote it up,
>>but I plan to use it in the future
>>on some other polynomial root structures.
>>(* root group where x^q+1=(x+1)^q: binomial expansion without x^q and 1*)
>>a=Flatten[Table[x/. NSolve[s[n]==0,x],{n,2,digits}]];
>b = Table[{Re[a[[n]]], Im[a[[n]]]}, {n, 1, Dimensions[a][[1]]}];
>ChopEnds = ListPlot[b, PlotRange -> {{-1, 2}, {-1, 1}}];
>central = ParametricPlot[{Cos[t], Sin[t]}, {t, 0, 2 Pi}];
>displ = ParametricPlot[{Cos[t] - 1, Sin[t]}, {t, 0, 2 Pi}];
>Show[ChopEnds, central, displ];
>Hi Roger,
>The roots are neatly herded onto unit circles centered on (0,0) and
>(-1,0), (except one point (-0.5, +/-1), as may be expected for complex
>roots of z^(1/n),(z+1)^(1/n) somehow with only negative real parts,
>|x|<1 .
>Regards. Nara

Respectfully, Roger L. Bagula
tftn at, 11759Waterhill Road, Lakeside,Ca 92040-2905,tel: 619-5610814 :
URL : 

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