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MathGroup Archive 2005

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Re: How can I simplify a series with some multiplicative factor?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg55668] Re: [mg55662] How can I simplify a series with some multiplicative factor?
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Sat, 2 Apr 2005 01:27:59 -0500 (EST)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

x^2 Sum[C[n] x^n,{n,0,Infinity}] /. 
    Sum->mySum /.
  x^m_. * mySum[term_, iter_] :> 
    Sum[term*x^m,iter]

Sum[x^(n + 2)*C[n], {n, 0, Infinity}]


Bob Hanlon

> 
> From: Zhou Jiang <jiangzhou_yz at yahoo.com>
To: mathgroup at smc.vnet.net
> Date: 2005/04/01 Fri AM 05:37:09 EST
> To: mathgroup at smc.vnet.net
> Subject: [mg55668] [mg55662] How can I simplify a series with some multiplicative 
factor?
> 
> 
> Hi, My colleagues,
> I want Mathematica to simplify the following expression
>  
> x^2 Sum[C[n] x^n ,{n,0,Infinity}]
>  
> I wrote Simplify[%] to do the job but the expression is not changed at all. 
How can I get the result something like
>  
> C[n] x^(n+2),
>  
> i.e., I hope Mathematica can move the x^2 term in the summation operator. 
Can anyone give me some idea? Thank you very much.
>  
> Daxin Shi
> 
> 


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