Re: How can I simplify a series with some multiplicative factor?
- To: mathgroup at smc.vnet.net
- Subject: [mg55668] Re: [mg55662] How can I simplify a series with some multiplicative factor?
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Sat, 2 Apr 2005 01:27:59 -0500 (EST)
- Reply-to: hanlonr at cox.net
- Sender: owner-wri-mathgroup at wolfram.com
x^2 Sum[C[n] x^n,{n,0,Infinity}] /.
Sum->mySum /.
x^m_. * mySum[term_, iter_] :>
Sum[term*x^m,iter]
Sum[x^(n + 2)*C[n], {n, 0, Infinity}]
Bob Hanlon
>
> From: Zhou Jiang <jiangzhou_yz at yahoo.com>
To: mathgroup at smc.vnet.net
> Date: 2005/04/01 Fri AM 05:37:09 EST
> To: mathgroup at smc.vnet.net
> Subject: [mg55668] [mg55662] How can I simplify a series with some multiplicative
factor?
>
>
> Hi, My colleagues,
> I want Mathematica to simplify the following expression
>
> x^2 Sum[C[n] x^n ,{n,0,Infinity}]
>
> I wrote Simplify[%] to do the job but the expression is not changed at all.
How can I get the result something like
>
> C[n] x^(n+2),
>
> i.e., I hope Mathematica can move the x^2 term in the summation operator.
Can anyone give me some idea? Thank you very much.
>
> Daxin Shi
>
>