DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?

*To*: mathgroup at smc.vnet.net*Subject*: [mg55802] DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?*From*: "Matt" <anonmous69 at netscape.net>*Date*: Wed, 6 Apr 2005 03:11:59 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

Hello, This isn't particularly important probably, however, I am trying to learn as much about Mathematica as possible, and I thought this might shed some light on a 'Why Mathematica does this or that' principle. I'm working my way through 'The Mathematica Guidebook for Programming' and on page 177, he gives an example as follows: In[39]:= DirectedInfinity[1 + I] DirectedInfinity[I] Out[39]:= DirectedInfinity[-(1 - I)/sqrt(2)] That puzzled me a bit, so I decided to see what Mathematica would do with just the first part: In[40]:= DirectedInfinity[1 + I] Out[40]:= DirectedInfinity[(1 + I)/sqrt(2)] I realize that (1 + I)/sqrt(2) is in the same direction as (1 + I), but why did Mathematica change it to the more 'strange' form? Thanks, Matt

**Follow-Ups**:**Re: DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?***From:*Andrzej Kozlowski <akoz@mimuw.edu.pl>

**Re: DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?***From:*Murray Eisenberg <murray@math.umass.edu>

**Re: DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?***From:*DrBob <drbob@bigfoot.com>