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MathGroup Archive 2005

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Re: Miscellaneous'WorldPlot'

  • To: mathgroup at smc.vnet.net
  • Subject: [mg55910] Re: [mg55870] Miscellaneous'WorldPlot'
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Sat, 9 Apr 2005 03:56:41 -0400 (EDT)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

$Version

5.1 for Mac OS X (January 27, 2005)

Needs["Miscellaneous`WorldPlot`"];

It doesn't seem to like exact values.  Force use of inexact numbers (e.g., I 
used 2. vice 2)

WorldPlot[World,WorldRange->{{-90,90},{-90,90}},
    WorldProjection->({
            2.*Cos[#1*Pi/10800]*Sin[#2*Pi/10800]/
                (1+Cos[#1*Pi/10800]*Cos[#2*Pi/10800]),
            2.*Sin[#1*Pi/10800]/
                (1+Cos[#1*Pi/10800]*Cos[#2*Pi/10800])}&)];


Bob Hanlon

> 
> From: "Hanka   Lakomá" <hana.lakoma at centrum.cz>
To: mathgroup at smc.vnet.net
> Date: 2005/04/08 Fri AM 01:36:53 EDT
> To: mathgroup at smc.vnet.net
> Subject: [mg55910] [mg55870] Miscellaneous'WorldPlot'
> 
> Dear Group,
> I try to get a map in stereographic projection in transverse position (the 
centre of the map is point 0°latitude, 0°longitude). 
> I have cartographic equations of this projection in wanted position. So I put 
them to WorldProjection:
> 
> Miscellaneous'WorldPlot'
> WorldPlot [Europe,
>     WorldRange->{{-90,90},{-90,90}},
>     WorldProjection->({2*Cos[#1*Pi/10800]*Sin[#2*Pi/10800]/
>                               (1+Cos[#1*Pi/10800]*Cos[#2*Pi/10800]),
>                               2*Sin[#1*Pi/10800]/
>                               (1+Cos[#1*Pi/10800]*Cos[#2*Pi/10800])}&)] 
> 
> and I get from Mathematica 4.2:
> WorldGraphics::"badproj" :
> The projection function {....,...} did not return a valid coordinate...
>   
> If I change Europe for another possible continent or state it gives the same 
type of error...
> If I change WorldRange for another possible it gives the same type of 
error...
> Is a problem in projection function and Why? I know from cartography 
textbooks that equations are correct...
> Any help would be appreciated.
> Thank you for your time and consideration.
> Hanka
> 
> 


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