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Re: Convincing Mathematica that Sqrt[a+b]Sqrt[ab]==Sqrt[a^2+b^2]
 To: mathgroup at smc.vnet.net
 Subject: [mg63312] Re: Convincing Mathematica that Sqrt[a+b]Sqrt[ab]==Sqrt[a^2+b^2]
 From: Bill Rowe <readnewsciv at earthlink.net>
 Date: Fri, 23 Dec 2005 05:08:35 0500 (EST)
 Sender: ownerwrimathgroup at wolfram.com
On 12/20/05 at 11:35 PM, hattons at globalsymmetry.com (Steven T.
Hatton) wrote:
>Is there a way to convince Mathematica to multiply
>Sqrt[a+b]Sqrt[ab] to produce Sqrt[a^2+b^2]?
Well there is:
In[1]:=
z = Sqrt[a + b]*Sqrt[a  b];
Sqrt[Expand[z^2]]
Out[2]=
Sqrt[a^2  b^2]

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