Re: Convincing Mathematica that Sqrt[a+b]Sqrt[a-b]==Sqrt[a^2+b^2]

*To*: mathgroup at smc.vnet.net*Subject*: [mg63312] Re: Convincing Mathematica that Sqrt[a+b]Sqrt[a-b]==Sqrt[a^2+b^2]*From*: Bill Rowe <readnewsciv at earthlink.net>*Date*: Fri, 23 Dec 2005 05:08:35 -0500 (EST)*Sender*: owner-wri-mathgroup at wolfram.com

On 12/20/05 at 11:35 PM, hattons at globalsymmetry.com (Steven T. Hatton) wrote: >Is there a way to convince Mathematica to multiply >Sqrt[a+b]Sqrt[a-b] to produce Sqrt[a^2+b^2]? Well there is: In[1]:= z = Sqrt[a + b]*Sqrt[a - b]; Sqrt[Expand[z^2]] Out[2]= Sqrt[a^2 - b^2] -- To reply via email subtract one hundred and four