Re: Replacement equivalence?

*To*: mathgroup at smc.vnet.net*Subject*: [mg63352] Re: Replacement equivalence?*From*: carlos at colorado.edu*Date*: Sat, 24 Dec 2005 16:03:00 -0500 (EST)*References*: <do6892$b1t$1@smc.vnet.net><dod6tt$4fd$1@smc.vnet.net> <200512231008.FAA25926@smc.vnet.net> <dojf3r$fpn$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Hmm... cant get it to work as stated. Can you try the idea in this benchmark test ClearAll[f,a,b,c,i]; f[b_,c_]:=1/(c+b^2); v=Table[{i,f[b,i]/.b^2->16},{i,-6,6}]; ListPlot[v,PlotJoined->True]; and see if the plot gap goes away? Thanks.

**Follow-Ups**:**Re: Re: Replacement equivalence?***From:*Pratik Desai <pdesai1@umbc.edu>

**References**:**Re: Replacement equivalence?***From:*carlos@colorado.edu