Re: Simplify problems for checking easy equalities...

*To*: mathgroup at smc.vnet.net*Subject*: [mg53887] Re: Simplify problems for checking easy equalities...*From*: "Kevin J. McCann" <kjm at KevinMcCann.com>*Date*: Wed, 2 Feb 2005 06:25:51 -0500 (EST)*References*: <ctnhah$erh$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Hmmm, I may have been mistaken in my last post. There is that old issue of 2*Pi*I; so, I guess Mathematica is giving the correct "general answer". Kevin David Park wrote: > Cyrus, > > Include the proper assumptions in the Simplify statement. > > Simplify[Log[x^n] - n*Log[x], n \[Element] Integers && x > 0] > 0 > > David Park > djmp at earthlink.net > http://home.earthlink.net/~djmp/ > > From: Cyrus Erik Eierud [mailto:cyruserik at tele2.se] To: mathgroup at smc.vnet.net > > Please Help! > > Thanks for all great answers I've already found here! > My problem is that I can not simplify what to me seems as a very > simple equality task. This is what I want Mathematica to return zero > for: > > in[1]:= FullSimplify[Log[x^n] - n*Log[x]] > > out[1]= -n Log[x] + Log[x^n]) > > I have used Simplify to check equalities, but the one above (and many > other equations similar to the one above) just don't simplify. Am I > doing anything wrong or does anyone know of a better way to check > equalities? > > Appreciate any help, > Cyrus Eierud, Student > cyruserik at tele2.se > > >