Re: Simplify problems for checking easy equalities...

• To: mathgroup at smc.vnet.net
• Subject: [mg53886] Re: Simplify problems for checking easy equalities...
• From: "Kevin J. McCann" <kjm at KevinMcCann.com>
• Date: Wed, 2 Feb 2005 06:25:50 -0500 (EST)
• References: <ctnhah\$erh\$1@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```David,

While your approach works, the identity is true regardless of the values
of x and n; so, it is curious that Simplify does not get it for the more
general case.

Kevin

David Park wrote:
> Cyrus,
>
> Include the proper assumptions in the Simplify statement.
>
> Simplify[Log[x^n] - n*Log[x], n \[Element] Integers && x > 0]
> 0
>
> David Park
>
> From: Cyrus Erik Eierud [mailto:cyruserik at tele2.se]
To: mathgroup at smc.vnet.net
>
>
> My problem is that I can not simplify what to me seems as a very
> simple equality task. This is what I want Mathematica to return zero
> for:
>
> in[1]:= FullSimplify[Log[x^n] - n*Log[x]]
>
> out[1]= -n Log[x] + Log[x^n])
>
> I have used Simplify to check equalities, but the one above (and many
> other equations similar to the one above) just don't simplify. Am I
> doing anything wrong or does anyone know of a better way to check
> equalities?
>
> Appreciate any help,
> Cyrus Eierud, Student
> cyruserik at tele2.se
>
>
>

```

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