Re: Re: grphing in Mathematica

*To*: mathgroup at smc.vnet.net*Subject*: [mg54462] Re: [mg54374] Re: grphing in Mathematica*From*: jeffb at wolfram.com*Date*: Sun, 20 Feb 2005 00:11:44 -0500 (EST)*References*: <bsire1sg1x3j@legacy> <200502190732.CAA06135@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

ContourPlot3D works just fine for this problem. Try the following: In[1]:= <<Graphics` In[2]:= ContourPlot3D[x^2+y^2+4 z^2,{x,-2,2},{y,-2,2},{z,-2,2},Contours->{1}, PlotPoints->{7,7},Axes->True,AxesLabel->{"x","y","z"}] Using version 5.0, I get a resulting ellipsoid in just a few seconds. -Jeff ------------- Jeff Bryant Wolfram Research, Inc. > On 17 Feb 05 12:08:58 -0500 (EST), Nick wrote: >>How do I graph the function x^2+y^2+4z^2=1? >>I am using Mathemetica version 4 and >>using ContourPlot3D doesn't work. > > > Mathematica plots implicit curves using ImplicitPlot, however, it's a > planar version only and as far as I am aware standard packages of > Mathematica > 5.1 implement no 3D version. If you are able to parametrize the curve, > use ParametricPlot3D. Otherwise you're left to create a suitable > package yourself. > > Jaroslav >

**References**:**Re: grphing in Mathematica***From:*highegg@centrum.cz (highegg)