       Re: Why does Inverse[M] hesitate?

• To: mathgroup at smc.vnet.net
• Subject: [mg54402] Re: [mg54370] Why does Inverse[M] hesitate?
• From: Bob Hanlon <hanlonr at cox.net>
• Date: Sun, 20 Feb 2005 00:08:02 -0500 (EST)
• Sender: owner-wri-mathgroup at wolfram.com

```Works fine here

\$Version

5.1 for Mac OS X (October 25, 2004)

A={{a11,a12},{a21,a22}};

B={{b11,b12},{b21,b22}};

Inverse[A].B

{{(a22*b11)/(a11*a22 - a12*a21) -
(a12*b21)/(a11*a22 - a12*a21),
(a22*b12)/(a11*a22 - a12*a21) -
(a12*b22)/(a11*a22 - a12*a21)},
{(a11*b21)/(a11*a22 - a12*a21) -
(a21*b11)/(a11*a22 - a12*a21),
(a11*b22)/(a11*a22 - a12*a21) -
(a21*b12)/(a11*a22 - a12*a21)}}

Bob Hanlon

>
> From: skirmantas.janusonis at yale.edu (Skirmantas)
To: mathgroup at smc.vnet.net
> Date: 2005/02/19 Sat AM 02:32:29 EST
> To: mathgroup at smc.vnet.net
> Subject: [mg54402] [mg54370] Why does Inverse[M] hesitate?
>
> I'm puzzled by the following in Mathematica 5.0 and 5.1:
> If I define a symbolic matrix A and a symbolic matrix B and ask to
> calculate Inverse[A].B, the output is the same input operation with
> the A and B expanded. I have re-input this output, I finally get the
> result.
>
>

```

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