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Re: Re: grphing in Mathematica


Needs["Graphics`ContourPlot3D`"]
ContourPlot3D[x^2 + y^2 + 4z^2 - 1, {x, -1, 1}, {y, -1, 1}, {z, -1, 1}, 
    PlotPoints -> 6, AspectRatio -> 1]


Neato :]


On Sat, 19 Feb 2005 02:32:39 -0500 (EST), highegg <highegg at centrum.cz> wrote:
> On 17 Feb 05 12:08:58 -0500 (EST), Nick wrote:
> >How do I graph the function x^2+y^2+4z^2=1?
> >I am using Mathemetica version 4 and
> >using ContourPlot3D doesn't work.
> 
> Mathematica plots implicit curves using ImplicitPlot, however, it's a
> planar version only and as far as I am aware standard packages of Mathematica
> 5.1 implement no 3D version. If you are able to parametrize the curve,
> use ParametricPlot3D. Otherwise you're left to create a suitable
> package yourself.
> 
> Jaroslav
> 
> 


-- 
Chris Chiasson
Kettering University
Mechanical Engineering
Graduate Student
1 810 265 3161


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