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MathGroup Archive 2005

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Re: Is Apart[ .. ] the correct way for denominator splitting?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg58555] Re: Is Apart[ .. ] the correct way for denominator splitting?
  • From: "Steve Luttrell" <steve_usenet at _removemefirst_luttrell.org.uk>
  • Date: Thu, 7 Jul 2005 05:35:44 -0400 (EDT)
  • References: <dag0hm$5a6$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Factor[2/(2x^2 - 1), Extension -> Sqrt[2]] // Apart

gives

-(Sqrt[2]/(Sqrt[2] - 2*x)) - Sqrt[2]/(Sqrt[2] + 2*x)

Steve Luttrell

"Jos Bergervoet" <Jos.MyName at Philips.com> wrote in message 
news:dag0hm$5a6$1 at smc.vnet.net...
>
> When I ask for:  Apart[2/(x^2-1), x]  I nicely get:
>
>    1/(x-1)  -  1/(x+1)
>
> But unfortunately  Apart[2/(2x^2-1), x]  does not give the same
> splitting of the denominator ( it just gives back 2/(2x^2-1) ).
>
> What is the correct way to see the denominator splitting with all
> terms first order (as one would use for integration, etc.)
>
> I found Andrzej Kozlowski's answer in message
>   http://groups-beta.google.com/group/sci.math/msg/4c9741832668c3b7
> from 2001, but I was wondering whether in the mean time a built-in
> function might have been added?
>
> -- Jos
> .
> 



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