Re: Is Apart[ .. ] the correct way for denominator splitting?

*To*: mathgroup at smc.vnet.net*Subject*: [mg58555] Re: Is Apart[ .. ] the correct way for denominator splitting?*From*: "Steve Luttrell" <steve_usenet at _removemefirst_luttrell.org.uk>*Date*: Thu, 7 Jul 2005 05:35:44 -0400 (EDT)*References*: <dag0hm$5a6$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Factor[2/(2x^2 - 1), Extension -> Sqrt[2]] // Apart gives -(Sqrt[2]/(Sqrt[2] - 2*x)) - Sqrt[2]/(Sqrt[2] + 2*x) Steve Luttrell "Jos Bergervoet" <Jos.MyName at Philips.com> wrote in message news:dag0hm$5a6$1 at smc.vnet.net... > > When I ask for: Apart[2/(x^2-1), x] I nicely get: > > 1/(x-1) - 1/(x+1) > > But unfortunately Apart[2/(2x^2-1), x] does not give the same > splitting of the denominator ( it just gives back 2/(2x^2-1) ). > > What is the correct way to see the denominator splitting with all > terms first order (as one would use for integration, etc.) > > I found Andrzej Kozlowski's answer in message > http://groups-beta.google.com/group/sci.math/msg/4c9741832668c3b7 > from 2001, but I was wondering whether in the mean time a built-in > function might have been added? > > -- Jos > . >