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Re: Is Apart[ .. ] the correct way for denominator splitting?
Factor[2/(2x^2 - 1), Extension -> Sqrt] // Apart gives -(Sqrt/(Sqrt - 2*x)) - Sqrt/(Sqrt + 2*x) Steve Luttrell "Jos Bergervoet" <Jos.MyName at Philips.com> wrote in message news:dag0hm$5a6$1 at smc.vnet.net... > > When I ask for: Apart[2/(x^2-1), x] I nicely get: > > 1/(x-1) - 1/(x+1) > > But unfortunately Apart[2/(2x^2-1), x] does not give the same > splitting of the denominator ( it just gives back 2/(2x^2-1) ). > > What is the correct way to see the denominator splitting with all > terms first order (as one would use for integration, etc.) > > I found Andrzej Kozlowski's answer in message > http://groups-beta.google.com/group/sci.math/msg/4c9741832668c3b7 > from 2001, but I was wondering whether in the mean time a built-in > function might have been added? > > -- Jos > . >