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Re: Mathematica can't calculate Fourier transform (Dirac mean position eigenfunction)
Thanks for your help. Does that mean I have no hope of transforming the wavefunction into r space? I'm also not sure what is meant by "absolute integrable". Does that just mean that the integral from zero to infinity exists? If so, why is Mathematica happy to transform functions such as 1, k, k^2 etc? Incidentally, for the Klein-Gordon case, the upper/lower components of the wavefunction were given by k ( (1+k^2)^(1/4) ± (1+k^2)^(-1/4) ) and that transformed without difficulty.