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MathGroup Archive 2005

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Re: simple cipher

  • To: mathgroup at smc.vnet.net
  • Subject: [mg55378] Re: [mg55364] simple cipher
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Mon, 21 Mar 2005 03:01:43 -0500 (EST)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

s1={1,0,1,0,0,1,0,1};
s2={L,r,o,w,e,v,y,e};

StringJoin[ToString/@s2[[Flatten[Position[s1,1]]]]]

Love

Inner[If[#1==0,"",ToString[#2]]&,s1,s2,StringJoin]

Love

StringJoin[If[#===0,"",ToString[#]]&/@(s1*s2)]

Love

In version 5.1

StringJoin[ToString/@Pick[s2,s1,1]]

Love


Bob Hanlon

> 
> From: zak <chocolatez at gmail.com>
To: mathgroup at smc.vnet.net
> Date: 2005/03/20 Sun AM 04:11:56 EST
> To: mathgroup at smc.vnet.net
> Subject: [mg55378] [mg55364] simple cipher
> 
> s1 = {1, 0, 1, 0, 0, 1, 0, 1}
> s2 = {L, r, o, w, e, v, y, e}
> 
> s1 is a kind of a sieve i want to look through to s2, so i could pick
> every letter in s2 wich correspond to every digit=1 in s1 so i could
> obtain the word "love", this is like the trivial ciphers we know in
> our childhood, i have the following approach, i hope there is other
> versions.
> 
> p = Flatten[Position[s1, 1]]
> out[]= {1, 3, 6, 8}
> 
> str = "";
> Do[str = StringJoin[str, ToString[s2[[p[[i]]]]]], {i, 1, 4}]
> str
> 
> Out[]= Love
> 
> thanks
> zak
> 
> 


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