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MathGroup Archive 2005

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Two related question. Question 1

  • To: mathgroup at smc.vnet.net
  • Subject: [mg57498] Two related question. Question 1
  • From: kazimir04 at yahoo.co.uk (Kazimir)
  • Date: Sun, 29 May 2005 21:00:17 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

I have two related question. Let me introduce a pure function

f = #1^2 + #2 &

Now. I want to make an operation over the function, for example to
find its square and to call the result (the expected function f = (#1^2
+ #2)^2 & ) c:

c=f^2

However, I do not obtain this, as 

c[a,b]

does not evaluate to (a+b)^2. Can anybody advise me how to obtain
such a function without long substitutions. I would like to obtain
something which is made for derivatives :

In[11]:=
Derivative[1][f]

Out[11]=
2 #1&

In[12]:=
Derivative[2][f]

Out[12]=
2&

Regards 

Vlad


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