Two related question. Question 1

*To*: mathgroup at smc.vnet.net*Subject*: [mg57498] Two related question. Question 1*From*: kazimir04 at yahoo.co.uk (Kazimir)*Date*: Sun, 29 May 2005 21:00:17 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

I have two related question. Let me introduce a pure function f = #1^2 + #2 & Now. I want to make an operation over the function, for example to find its square and to call the result (the expected function f = (#1^2 + #2)^2 & ) c: c=f^2 However, I do not obtain this, as c[a,b] does not evaluate to (a+b)^2. Can anybody advise me how to obtain such a function without long substitutions. I would like to obtain something which is made for derivatives : In[11]:= Derivative[1][f] Out[11]= 2 #1& In[12]:= Derivative[2][f] Out[12]= 2& Regards Vlad

**Follow-Ups**:**Re: Two related question. Question 1***From:*Andrzej Kozlowski <andrzej@akikoz.net>