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MathGroup Archive 2006

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Re: Bug or feature ?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg72384] Re: Bug or feature ?
  • From: "Steve Luttrell" <steve_usenet at _removemefirst_luttrell.org.uk>
  • Date: Sat, 23 Dec 2006 06:14:46 -0500 (EST)
  • References: <emggb8$2i1$1@smc.vnet.net>

Evaluate this

PlotPoints /. Options[PolarPlot]

to find that the default number of points used to generate the plot is 25.

You can fix your problem by overriding the default with a larger value.

For instance:

PolarPlot[Sin[t]^2 Cos[t]^2, {t, 0, 21},PlotPoints->100]

Steve Luttrell
West Malvern, UK

"Giovanni Resta" <g.restaxxx at cutTheXXXiit.cnr.it> wrote in message 
news:emggb8$2i1$1 at smc.vnet.net...
> Please, try this with Mathematica (5.2):
>
> << Graphics`Graphics`
>
> PolarPlot[Sin[t]^2 Cos[t]^2, {t, 0, 2Pi}]
>
> PolarPlot[Sin[t]^2 Cos[t]^2, {t, 0, 21}]
>
> compare the two graphics.
>
> In the second (t is between zero and twentyone)
> I got a spurios segment between 3rd and 4th quadrants.
>
> Can you tell me why ?
>
> (Btw, I got this just playing for one minute or two
> with PolarPlot. The "21" was a typo...)
>
> g.
> 



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