Re: Bug or feature ?
- To: mathgroup at smc.vnet.net
- Subject: [mg72384] Re: Bug or feature ?
- From: "Steve Luttrell" <steve_usenet at _removemefirst_luttrell.org.uk>
- Date: Sat, 23 Dec 2006 06:14:46 -0500 (EST)
- References: <emggb8$2i1$1@smc.vnet.net>
Evaluate this
PlotPoints /. Options[PolarPlot]
to find that the default number of points used to generate the plot is 25.
You can fix your problem by overriding the default with a larger value.
For instance:
PolarPlot[Sin[t]^2 Cos[t]^2, {t, 0, 21},PlotPoints->100]
Steve Luttrell
West Malvern, UK
"Giovanni Resta" <g.restaxxx at cutTheXXXiit.cnr.it> wrote in message
news:emggb8$2i1$1 at smc.vnet.net...
> Please, try this with Mathematica (5.2):
>
> << Graphics`Graphics`
>
> PolarPlot[Sin[t]^2 Cos[t]^2, {t, 0, 2Pi}]
>
> PolarPlot[Sin[t]^2 Cos[t]^2, {t, 0, 21}]
>
> compare the two graphics.
>
> In the second (t is between zero and twentyone)
> I got a spurios segment between 3rd and 4th quadrants.
>
> Can you tell me why ?
>
> (Btw, I got this just playing for one minute or two
> with PolarPlot. The "21" was a typo...)
>
> g.
>