[Date Index]
[Thread Index]
[Author Index]
Re: Utilizing the Result From Solve[]
*To*: mathgroup at smc.vnet.net
*Subject*: [mg64143] Re: [mg64099] Utilizing the Result From Solve[]
*From*: "Erickson Paul-CPTP18" <Paul.Erickson at Motorola.com>
*Date*: Thu, 2 Feb 2006 00:07:03 -0500 (EST)
*Sender*: owner-wri-mathgroup at wolfram.com
Hopefully there is a more general solution for this, but I've used in
that past
z = Solve[z + 2 == 3, z][[1, 1, 2]] (* which is a little hard to
understand ... *)
Or
z = z /. Solve[z + 2 == 3, z][[1]] (* which is a little better, but ...
*)
The z /. ... Converts the rule into a list and therefore that form can
be used for converting any rule to a list of one element. The [[1]]
(Part) pulls out the number. I've always been interested in getting to
the number embedded in a larger equation, so assigning it as the value
to the same variable as above will be a little confusing especially on
subsequent evaluation within the same kernel unless you do an explicit
clear. I'd suggest a separate variable name, if so needed like:
a = z /. Solve[z + 2 == 3, z][[1]]
Paul
-----Original Message-----
From: Shyam Guthikonda [mailto:shyamguth at gmail.com]
To: mathgroup at smc.vnet.net
Subject: [mg64143] [mg64099] Utilizing the Result From Solve[]
If I am solving a simple equation, such as: Solve[z+2 = = 3,z], this
returns {{z->1}}. How can I easily get the result, 1? Solve[] returns
the solution in rule form.
The current method I use to just get the result looks very ugly. Is
there an easier way to do this?
Here is my current method:
ReplaceAll[z, First[ First[ Solve[ z + 2 = = 3, z ]]]]; z = %;
Now I can use z as a normal variable.
Thanks!
_Shyam
Prev by Date:
**Re: does anybody know how to find the inverse Laplace transform of this wierd thing?**
Next by Date:
**Re: Singularities at end point in integrations...**
Previous by thread:
**Re: Utilizing the Result From Solve[]**
Next by thread:
**Re: Utilizing the Result From Solve[]**
| |