       Re: Utilizing the Result From Solve[]

• To: mathgroup at smc.vnet.net
• Subject: [mg64109] Re: [mg64099] Utilizing the Result From Solve[]
• From: "Maarten van der Burgt" <maarten.vanderburgt at icos.be>
• Date: Thu, 2 Feb 2006 00:04:52 -0500 (EST)
• Sender: owner-wri-mathgroup at wolfram.com

```Shyam,

Your method is correct but you can do it a bit shorter:
sol =Solve[z+2==3,z]
z = z/.sol[]

Hope this helps

Maarten

Shyam
Guthikonda           To:     mathgroup at smc.vnet.net
<shyamguth@gm        cc:
ail.com>             Subject: [mg64109]     [mg64099] Utilizing the Result From Solve[]

01/02/2006
10:34

If I am solving a simple equation, such as: Solve[z+2 = = 3,z], this
returns {{z->1}}. How can I easily get the result, 1? Solve[] returns
the solution in rule form.

The current method I use to just get the result looks very ugly. Is
there an easier way to do this?

Here is my current method:

ReplaceAll[z, First[ First[ Solve[ z + 2 = = 3, z ]]]];
z = %;

Now I can use z as a normal variable.

Thanks!
_Shyam

```

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