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MathGroup Archive 2006

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Re: Mathematica:recursion with 2 arguments?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg64401] Re: [mg64353] Mathematica:recursion with 2 arguments?
  • From: Pratik Desai <pdesai1 at umbc.edu>
  • Date: Wed, 15 Feb 2006 03:32:37 -0500 (EST)
  • References: <200602130815.DAA12589@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

ddjjjkkkk wrote:

>Hi,everybody:
>My English is a little poor.But I have a very flustered problem to consult you.Who can help me? Here is the prob:
>IF function f(m,n)(m,n are non-negative integers)satisfying 3 conditions: f(0,n)=n+1,f(m+1,0)=f(m,1) and f(m+1,n+1)=f[m,f(m+1,n)],then how can we use Wolfram's Mathematica to solve f(m,1),f(m,2),f(m,3) and so on.I can get f(1,n)=n+2,f(2,n)=n+3,f(3,n)=2^(n+3)-3 by hand and pen(but how by Mathematica?).Surely,f(4,n) is very complicated.
>Who can use Mathematica's language (recursion or iteration etc.) to solve them out? Friends,help me--a poor person,please!!!!!!
>  
>
Have you tried RSolve???


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