Mathematica:recursion with 2 arguments?

*To*: mathgroup at smc.vnet.net*Subject*: [mg64353] Mathematica:recursion with 2 arguments?*From*: ddjjjkkkk <noble_c at hotmail.com>*Date*: Mon, 13 Feb 2006 03:15:15 -0500 (EST)*Sender*: owner-wri-mathgroup at wolfram.com

Hi,everybody: My English is a little poor.But I have a very flustered problem to consult you.Who can help me? Here is the prob: IF function f(m,n)(m,n are non-negative integers)satisfying 3 conditions: f(0,n)=n+1,f(m+1,0)=f(m,1) and f(m+1,n+1)=f[m,f(m+1,n)],then how can we use Wolfram's Mathematica to solve f(m,1),f(m,2),f(m,3) and so on.I can get f(1,n)=n+2,f(2,n)=n+3,f(3,n)=2^(n+3)-3 by hand and pen(but how by Mathematica?).Surely,f(4,n) is very complicated. Who can use Mathematica's language (recursion or iteration etc.) to solve them out? Friends,help me--a poor person,please!!!!!!

**Follow-Ups**:**Re: Mathematica:recursion with 2 arguments?***From:*Pratik Desai <pdesai1@umbc.edu>