Re: Re: Counting circles (digital image processing)

• To: mathgroup at smc.vnet.net
• Subject: [mg64531] Re: [mg64463] Re: Counting circles (digital image processing)
• From: "Maarten van der Burgt" <maarten.vanderburgt at icos.be>
• Date: Mon, 20 Feb 2006 22:31:05 -0500 (EST)
• Sender: owner-wri-mathgroup at wolfram.com

```Hallo,

I think the function KMeans[ ] in the Digital Image Processing package is
the clustering function you are looking for.
Have a look in the User`s Guide section 7.5 Segmentation by Clustering.

Maarten

|--------+--------------------------------->
|        |          "Jens-Peer Kuska"      |
|        |          <kuska at informatik.uni-l|
|        |          eipzig.de>             |
|        |                                 |
|        |          18/02/2006 08:49       |
|        |                                 |
|--------+--------------------------------->
>------------------------------------------------------------------------------------------------------------|
|                                                                                                            |
|       To:     mathgroup at smc.vnet.net                                                                       |
|       cc:                                                                                                  |
|       Subject: [mg64531]     [mg64463] Re: Counting circles (digital image processing)                               |
>------------------------------------------------------------------------------------------------------------|

Hi,

label the connected components in the binarized image.
For the radius I would suggest to use a distance transform on
the binary image and the maximum value of the distance transform

Regards
Jens
"Alexander" <beginning.physst at mail.ru> schrieb im
Newsbeitrag news:dt488e\$2hk\$1 at smc.vnet.net...
| Dear Mathgroup!
|
| Suppose we have a picture with a set of white
circles on a black
| background.
| How can we count circles and measure their
| system???
|
| Alexander.
|

```

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