Re: replacement rule and sparsearray question

*To*: mathgroup at smc.vnet.net*Subject*: [mg71326] Re: [mg71297] replacement rule and sparsearray question*From*: Sseziwa Mukasa <mukasa at jeol.com>*Date*: Wed, 15 Nov 2006 06:43:21 -0500 (EST)*References*: <200611141006.FAA06663@smc.vnet.net>

On Nov 14, 2006, at 5:06 AM, Arkadiusz.Majka at gmail.com wrote: > Hi, > > How can I apply a replacement rule to sparse array, e.g > > SparseArray[{1,2,3}]/.{2->222} > > and obtain the same result as for {1,2,3}/.{2->222} (what is > {1,222,3}. > > I DON'T want to call Normal before. Just replace the rule and make a new array: a=SparseArray[{1->1,2->2,3->3}]; b=SparseArray[ArrayRules[a]/.({2}->_)->({2}->222)] Regards, Ssezi

**References**:**replacement rule and sparsearray question***From:*Arkadiusz.Majka@gmail.com