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Re: Re: Please help: How to use Mathematica to get Parametric solution for a transcendental equation?

• To: mathgroup at smc.vnet.net
• Subject: [mg69295] Re: [mg69222] Re: Please help: How to use Mathematica to get Parametric solution for a transcendental equation?
• From: Leonxf <leonxf at gmail.com>
• Date: Tue, 5 Sep 2006 05:31:16 -0400 (EDT)
• Sender: owner-wri-mathgroup at wolfram.com

Sorry. I just copied from Mathematica and pasted it. I have no idea why it
becomes something unreadable.

The function is just one:

A*(1+G)+a*[(1+G)^t]=T, where A,a,t,T are all positive real numbers, and t is
no larger than 1.

Thanks.

Leon


On 9/2/06, Jens-Peer Kuska <kuska at informatik.uni-leipzig.de> wrote:
>
> Hi,
>
> can you try to use correct Mathematica syntax ??
> This means is D7(1+G) an algebraic bracket or a function
> call and is D7[(1+G)^t] an algebraic bracket or a function
> call and what does "====" mean together with "=" and
> have you a single equation or several ones ??
> Regards
>   Jens
>
>
> > Leonxf wrote:
> > Dear All,
> >
> > I am new to the group. Nice to have all of you here.
> >
> > I have an urgent question: I have a transcendental equation, which is
> >
> > A=D7(1 + G) + a=D7[(1 + G)^t] ==== T, where A,a,T,t are unknown, but
> A,a,T,=
> > t
> > are all positive real numbers, and t is no greater than 1. (I use ^ sign
> > here to indicate "to the power of").
> >
> > What I hope to get is a parametric expression for G, say, G==f(A,a,t,T)
> for
> > some fucntion f().
> >
> > Is there anyway to do that? I noticed someone asked a similar question
> > before, and an answer is to get Taylor Series, if that is the only way,
> how
> > to do that?
> >
> > Thank you in advance.
> >
> > Leon
> >
>
>