Re: Re: Please help: How to use Mathematica to get Parametric solution for a transcendental equation?

*To*: mathgroup at smc.vnet.net*Subject*: [mg69295] Re: [mg69222] Re: Please help: How to use Mathematica to get Parametric solution for a transcendental equation?*From*: Leonxf <leonxf at gmail.com>*Date*: Tue, 5 Sep 2006 05:31:16 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

Sorry. I just copied from Mathematica and pasted it. I have no idea why it becomes something unreadable. The function is just one: A*(1+G)+a*[(1+G)^t]=T, where A,a,t,T are all positive real numbers, and t is no larger than 1. Thanks. Leon On 9/2/06, Jens-Peer Kuska <kuska at informatik.uni-leipzig.de> wrote: > > Hi, > > can you try to use correct Mathematica syntax ?? > This means is D7(1+G) an algebraic bracket or a function > call and is D7[(1+G)^t] an algebraic bracket or a function > call and what does "====" mean together with "=" and > have you a single equation or several ones ?? > Regards > Jens > > > > Leonxf wrote: > > Dear All, > > > > I am new to the group. Nice to have all of you here. > > > > I have an urgent question: I have a transcendental equation, which is > > > > A=D7(1 + G) + a=D7[(1 + G)^t] ==== T, where A,a,T,t are unknown, but > A,a,T,= > > t > > are all positive real numbers, and t is no greater than 1. (I use ^ sign > > here to indicate "to the power of"). > > > > What I hope to get is a parametric expression for G, say, G==f(A,a,t,T) > for > > some fucntion f(). > > > > Is there anyway to do that? I noticed someone asked a similar question > > before, and an answer is to get Taylor Series, if that is the only way, > how > > to do that? > > > > Thank you in advance. > > > > Leon > > > >