       Re: translating code from True Basic to Mathematica

• To: mathgroup at smc.vnet.net
• Subject: [mg69420] Re: translating code from True Basic to Mathematica
• From: Paul Abbott <paul at physics.uwa.edu.au>
• Date: Tue, 12 Sep 2006 06:52:25 -0400 (EDT)
• Organization: The University of Western Australia
• References: <ee0sfs\$b1g\$1@smc.vnet.net>

```In article <ee0sfs\$b1g\$1 at smc.vnet.net>,
Roger Bagula <rlbagula at sbcglobal.net> wrote:

> I did some IFS based on {r,theta} variable iteration
> several years back.
> One seems to have become a favorite.
> Arg[] and ArcTan[] in Mathematica aren't exactly the same function as
> Angle() in True Basic!
>
> A delicate lace like fractal that I did several years back is at:
> http://local.wasp.uwa.edu.au/~pbourke/fractals/lace/lace.basic
>
> C code is at:
> http://local.wasp.uwa.edu.au/~pbourke/fractals/lace/lace.c
>
> My best effort so far at a Mathematica translation is:
> Clear[ifs, f1, f2, f3, f4, f]
> f1[{x_, y_}] = N[{ -Cos[Arg[x + 1/2 + I*(y + Sqrt/2)]]*
>     Sqrt[x^2 +
>            y^2] - 1/
>                   2, -Sin[
>                     Arg[x + 1/2 + I*(y +
>                        Sqrt/2)]]*Sqrt[x^2 + y^2] - Sqrt/2}]/2;
> f2[{x_, y_}] = N[{ -Cos[Arg[x + 1/2 +
>           I*(y - Sqrt/2)]]*Sqrt[x^2 + y^2] -
>                       1/2, -Sin[Arg[x + 1/2 + I*(y -
> Sqrt/2)]]*Sqrt[x^2 +
>                     y^2] + Sqrt/2}]/2;
> f3[{x_, y_}] = N[{ -Cos[Arg[x - 1 +
>     I*(y)]]*Sqrt[x^2 + y^2] + 1, -Sin[Arg[x -
>                 1 + I*(y)]]*Sqrt[x^2 + y^2]}]/2;
> f4[{x_, y_}] = N[{ -Cos[Arg[x + I*(y)]]*Sqrt[x^2 + y^2], -Sin[Arg[x +
> I*(y)]]*
>         Sqrt[x^2 + y^2]}]/2;
> f[x_] := Which[(r = Random[]) <= 1/4, f1[x],
>     r <= 1/2, f2[x],
>     r <= 3/4, f3[x],
>     r <= 1.00, f4[x]]
> ifs[n_] := Show[Graphics[{PointSize[.001],
>     Map[Point, NestList[f, {0, 0.001}, n]]}], AspectRatio -> Automatic]
> ifs

Since Mathematica supports complex algebra, you can re-write this more
succintly as

g[z_] = E^( I Pi/3) + Abs[z] E^(I Arg[z + E^( I Pi/3)]);
g[z_] = E^(-I Pi/3) + Abs[z] E^(I Arg[z + E^(-I Pi/3)]);
g[z_] = Abs[z] E^(I Arg[z - 1]) - 1;
g[z_] = z;

f[z_]:= -1/2 g[Random[Integer, {1, 4}]][z]

ifs[n_] := Show[Graphics[{PointSize[0.001],
NestList[f, 0.001 I, n] /. Complex[a_, b_] :> Point[{a, b}]}],
AspectRatio -> Automatic]

In this way it is much easier to see the effect of each of the randomly
selected transformation functions.

Cheers,
Paul

_______________________________________________________________________
Paul Abbott                                      Phone:  61 8 6488 2734
School of Physics, M013                            Fax: +61 8 6488 1014
The University of Western Australia         (CRICOS Provider No 00126G)
AUSTRALIA                               http://physics.uwa.edu.au/~paul

```

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