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MathGroup Archive 2007

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Re: numerical inversion of laplace transform

  • To: mathgroup at smc.vnet.net
  • Subject: [mg74927] Re: numerical inversion of laplace transform
  • From: "dantimatter" <dantimatter at gmail.com>
  • Date: Wed, 11 Apr 2007 02:02:47 -0400 (EDT)
  • References: <evfk8c$5bk$1@smc.vnet.net>

hi dimitris,

sorry about that posting.  here we go again:

G(t)=6.06 - 4.17*Cos[(Pi*t)/84] + 1.19*Cos[(Pi*t)/42] -
2.95*Sin[(Pi*t)/84] + 0.71*Sin[(Pi*t)/42]
p(t) = UnitStep[33.6 - t]

so that the Laplace-transformed function that I'd like to invert, G(s)/
p(s) is

G(s)/p(s) =
(3.83*^7*E^(33.6*s)*(0.0029 - 0.049*s + s^2)*(0.0054 + 0.031*s + s^2))/
((-1. + E^(33.6*s))*(Pi^2 + 1764.*s^2)*(Pi^2 + 7056.*s^2))

thanks!
dan



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