Re: Other PDE heat equation

*To*: mathgroup at smc.vnet.net*Subject*: [mg79709] Re: Other PDE heat equation*From*: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>*Date*: Thu, 2 Aug 2007 03:53:24 -0400 (EDT)*Organization*: Uni Leipzig*References*: <f8pkd4$2vr$1@smc.vnet.net>*Reply-to*: kuska at informatik.uni-leipzig.de

Hi, for you second order equation you have two drgrees of freedom in thr space direction, i.e., you can give (u[-L,t] and u[L,t]) or (u[-L,t] and D[u[x,t,x]/. x->L) or (D[u[x,t,x]/. x->-L and u[L,t]) but you can't give three conditions, espcial not for inner points. In the inner points of the interval the differential equation rules and not any condition. But you can solve the equation on the interval x in [0,L] and use the symmetry of your equation (and the solution). Regards Jens Miguel wrote: > How can I to resolve the unidirectional heat transmission for a plate > o slab: > > a=0.03;hc=1890;k=34;L=0.03; > > NDSolve[{a D[u[x,t],{x,2}]==D[u[x,t],t], > u[L,0]==600, (* Initial value: the plate has the same temperature *) > u[-L,0]==600, > u[0,0]==600, > (D[u[x,t],x]/.x->0)==0 (* Max. in centre *) > (D[u[x,t],x]/.x->L)==(-hc/k)(u[L,t]-600) (* Q convection = Q > conduction *) > u[L,t]==u[-L,t]}, (* Temper. symetric *) > u[x,t],{x,-L,L},{t,0,10}] > > NDSolve::ivone: Boundary values may only be specified for one \ > independent variable. Initial values may only be specified at one \ > value of the other independent variable. >> > > Where is my error? > > Thanks > >