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Re: Convert Binary Image to Column Vector
*To*: mathgroup at smc.vnet.net
*Subject*: [mg83992] Re: Convert Binary Image to Column Vector
*From*: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
*Date*: Thu, 6 Dec 2007 02:46:27 -0500 (EST)
*Organization*: Uni Leipzig
*References*: <fj65hr$fp1$1@smc.vnet.net>
*Reply-to*: kuska at informatik.uni-leipzig.de
Hi,
What is a binary image for you ? something like
img=Graphics[Raster[{{0, 1}, {1, 0}}, {{0, 0}, {2, 2}}, {0, 1},
ColorFunction -> GrayLevel], AspectRatio -> Automatic]
??
or something like bm={{0, 1}, {1, 0}} ..
Since Flatten[bm] will make a vector out of a matrix as well
as Flatten[img[[1,1]]] it is not clear what ordering you perfer, i.e.
should in bm[[j,i]] the index i run first or the index j. This is
what you change with Transpose[].
Regards
Jens
Tara.Ann.Lorenz at gmail.com wrote:
> Can a 30x30 binary image be converted directly into a column vector of
> 900 components in Mathematica? Or must the image first be put into
> matrix form? I am using the command:
> Flatten@Transpose@t1, where t1 is my binary image, and it seems to
> give me a vector but I'm not sure if it's the one that I desire.
>
> If I first convert my image into matrix form and define my matrix as
> "m" and then use this command,
> Flatten@Transpose@m, then I get an output of "Transpose[...]" and my
> 30 x 30 matrix is explicitly written within the Transpose brackets.
> This does not provide me a column vector with 900 components, which is
> what I am looking for.
>
> Any thoughts?
>
> Thanks.
>
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