       Re: help with mathematica 5.2-Vector

• To: mathgroup at smc.vnet.net
• Subject: [mg84492] Re: [mg84487] help with mathematica 5.2-Vector
• From: Bob Hanlon <hanlonr at cox.net>
• Date: Sat, 29 Dec 2007 19:58:41 -0500 (EST)

```Lists are not vectors.

a = {1, 2, 3};
b = {2, 3, 4};
c = a - b;

Show[Graphics3D[
Line[{{0, 0, 0}, #}] & /@ {a, -b, c}}]],
Axes -> True]

Bob Hanlon

---- george <mariuska1989 at hotmail.com> wrote:
> Hello! I started recently working with Mathematica 5.2 and I face a problem that I'm trying to solve but I can't find the solution: I have 2 vectors, let's say:
> a=(1,2,3)
> b=(2,3,4)
> I want to make the graph for c=a-b(it should be an arrow, at 3-Dimensions, right?).
> I use the command ListPlot(c), nevertheless it produces  cartesian axes with 2 points(I suppose these are the heads of the arrows, but I'm not sure).
> Is there anything to do in order to make the correct graph?
> (if the graph is not supposed to be an arrow, is not supposed to be at 3-Dimensions, it would be really helpful if someone could explain me why).