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Re: help with mathematica 5.2-Vector

  • To: mathgroup at smc.vnet.net
  • Subject: [mg84492] Re: [mg84487] help with mathematica 5.2-Vector
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Sat, 29 Dec 2007 19:58:41 -0500 (EST)
  • Reply-to: hanlonr at cox.net

Lists are not vectors.

a = {1, 2, 3};
b = {2, 3, 4};
c = a - b;

Show[Graphics3D[
  Thread[{{Red, Blue, Green}, 
    Line[{{0, 0, 0}, #}] & /@ {a, -b, c}}]],
 Axes -> True]


Bob Hanlon

---- george <mariuska1989 at hotmail.com> wrote: 
> Hello! I started recently working with Mathematica 5.2 and I face a problem that I'm trying to solve but I can't find the solution: I have 2 vectors, let's say:
> a=(1,2,3)
> b=(2,3,4)
> I want to make the graph for c=a-b(it should be an arrow, at 3-Dimensions, right?).
> I use the command ListPlot(c), nevertheless it produces  cartesian axes with 2 points(I suppose these are the heads of the arrows, but I'm not sure).
> Is there anything to do in order to make the correct graph?
> (if the graph is not supposed to be an arrow, is not supposed to be at 3-Dimensions, it would be really helpful if someone could explain me why).
> Thank you in advance.
> 



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