Re: Graphics package in v6
- To: mathgroup at smc.vnet.net
- Subject: [mg78413] Re: [mg78406] Graphics package in v6
- From: Carl Woll <carlw at wolfram.com>
- Date: Sun, 1 Jul 2007 03:44:19 -0400 (EDT)
- References: <200706301012.GAA09513@smc.vnet.net>
Jaccard Florian wrote:
>Dear group,
>
>I'm a convinced Mathematica user, I love the new features I discover in v6, but I think the Graphics package was very useful in v5 and I'm missing it.
>
>For example, it was very easy to obtain the 3D plot of a surface of revolution around the x-axis with SurfaceOfRevolution.
>
>Let us take the revolution of y=x^2 around the x-axis :
>
><< "Graphics`"
>SurfaceOfRevolution[x^2, {x, 0, 2}, RevolutionAxis -> {1, 0, 0}]
>
>Not possible without cheating if using RevolutionPlot3D, isn't it=A0?
>
>
I think this issue has already been discussed in thread:
http://tinyurl.com/3duktb*
*
>Or you could have a nice plot of implicit functions, with the ticks on the x- and y-axis, using ImplicitPlot...
>
>Example :
>
><< "Graphics`"
>ImplicitPlot[x^3*y + x*y^3 == 2, {x, -3, 3}, {y, -3, 3}]
>
>Not possible using CountourPlot without cheating, isn't it?
>
>(I consider the following as cheating :
>Show[Plot[0, {x, -3, 3}, PlotRange -> {-3, 3},
> AspectRatio -> Automatic],
> ContourPlot[x^3*y + x*y^3 == 2, {x, -3, 3}, {y, -3, 3},
> Axes -> True,
> AxesOrigin -> {0, 0}, PerformanceGoal -> "Quality",
> PlotPoints -> 150]]
>)
>
>
>
Doesn't
ContourPlot[x^3 y+x y^3==2, {x,-3,3}, {y,-3,3}, Axes->True, Frame->False]
do the same thing as the ImplicitPlot example?
Carl Woll
Wolfram Research
>I tried: it still works in v6, but the whole package is declared obsolete, and there is no help anymore available.
>
>Am I missing something? Or am I the only guy who would appreciate the re-apparition of some lost features in the future v.6.1?
>
>Reactions welcome!
>
>Regards
>
>Florian Jaccard
>
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>
>
>