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MathGroup Archive 2007

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Re: how to find complete integral of pde

  • To: mathgroup at smc.vnet.net
  • Subject: [mg74419] Re: how to find complete integral of pde
  • From: "bhargavi" <bhargavi.math at gmail.com>
  • Date: Tue, 20 Mar 2007 05:56:55 -0500 (EST)
  • References: <etlqcn$rap$1@smc.vnet.net><etnif8$dl7$1@smc.vnet.net>

hi, tx alot for ur reply.
i copied input from mathematica5.2, n pasting here.
\!\(CompleteIntegral[D[u[x, y], x]*1.5*\((
    1 - 4\ y\^2)\) == \ Br\ 144\ y\^2\  + D[u[x, y], y]^2, u[x, y],
{x, y}]\)

i tried like what u said press Ctrl+Shift+I (after selecting the
cell(s)).still i did't get it.
could u try my input in ur mathematica n get me.plz..
thanking you
bhargavi



 dimitris wrote:
> =CF/=C7 bhargavi =DD=E3=F1=E1=F8=E5:
> > hi to all,can anyone how to find complete integral in mathematica. i
> > tried like this.but the output is same as input. \!\
> > (CompleteIntegral[1.5\ \((1 - 4\ y\^2)\)\ D[=CE=B8[x, y],
> >           x] == \ D[=CE=B8[x, y], y]^2 + 144\ Br\ y, =CE=B8[x=
> , y], {x, =
> > y}]\).
> > if anybody knows please suggest me.
> > bhargavi
>
> Your post is unreadable.
> Try to repost again this time by converting your Mathematica
> expressions to InputForm,
> by simply press Ctrl+Shift+I (after selecting the cell(s)).
>
> Dimitris



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