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Re: Re: How to get sqrt(Year^2)===Year?
"Full" in FullSimplify is unnecessary, and Element[Year, Reals] is redundant here: Simplify[(Year^2)^(1/2),Year>=0] Year Jens-Peer Kuska wrote: > Hi, > > FullSimplify[Year == (Year^2)^(1/2), Element[Year, Reals] && Year > 0] > > gives True > > Regards > Jens > Hatto von Aquitanien wrote: >> If I have some expression which takes the square root of a square, it >> evaluates leaving the whole square root expression unchanged. >> >> Year == (Year^2)^(1/2) >> >> just returns what I entered when evaluated. >> >> Year == Year >> >> evaluates to True. >> >> How do I persuade Mathematica to evaluate the first expression completely? > -- Murray Eisenberg murray at math.umass.edu Mathematics & Statistics Dept. Lederle Graduate Research Tower phone 413 549-1020 (H) University of Massachusetts 413 545-2859 (W) 710 North Pleasant Street fax 413 545-1801 Amherst, MA 01003-9305