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Re: How to get sqrt(Year^2)===Year?

• To: mathgroup at smc.vnet.net
• Subject: [mg75769] Re: How to get sqrt(Year^2)===Year?
• From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
• Date: Thu, 10 May 2007 05:12:58 -0400 (EDT)
• Organization: Uni Leipzig
• References: <f1s1v4$fip$1@smc.vnet.net>
• Reply-to: kuska at informatik.uni-leipzig.de

Hi,

FullSimplify[Year == (Year^2)^(1/2), Element[Year, Reals] && Year > 0]

gives True

Regards
   Jens
Hatto von Aquitanien wrote:
> If I have some expression which takes the square root of a square, it
> evaluates leaving the whole square root expression unchanged.  
> 
> Year == (Year^2)^(1/2)
> 
> just returns what I entered when evaluated.
> 
> Year == Year
> 
> evaluates to True.
> 
> How do I persuade Mathematica to evaluate the first expression completely?

• Follow-Ups:
  • Re: Re: How to get sqrt(Year^2)===Year?
    • From: Murray Eisenberg <murray@math.umass.edu>