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Re: How to get sqrt(Year^2)===Year?


Hi,

FullSimplify[Year == (Year^2)^(1/2), Element[Year, Reals] && Year > 0]

gives True

Regards
   Jens
Hatto von Aquitanien wrote:
> If I have some expression which takes the square root of a square, it
> evaluates leaving the whole square root expression unchanged.  
> 
> Year == (Year^2)^(1/2)
> 
> just returns what I entered when evaluated.
> 
> Year == Year
> 
> evaluates to True.
> 
> How do I persuade Mathematica to evaluate the first expression completely?


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