Re: Re: v. 6, third argument to rectangle

*To*: mathgroup at smc.vnet.net*Subject*: [mg75849] Re: [mg75845] Re: v. 6, third argument to rectangle*From*: Andrzej Kozlowski <akoz at mimuw.edu.pl>*Date*: Sat, 12 May 2007 02:58:28 -0400 (EDT)*References*: <f21e5e$6e7$1@smc.vnet.net> <200705111030.GAA08108@smc.vnet.net>

It's true that it works, but the fact that it works seems to be now undocumented. Mathematica 5.2 documentation states: "In Rectangle[{a, a}, {a, a}, graphics], graphics can be any graphics object." but there does not seem to be any such statement in 6.0 (?) Andrzej Kozlowski On 11 May 2007, at 19:30, Jens-Peer Kuska wrote: > Hi, > > that's nonsense -- Rectangle[] work as in the > versions before with a third argument. > > > Regards > Jens > > rip pelletier wrote: >> hi, >> >> thru 5.2 we could display, for example, 2 graphs side-by-side by >> using a >> third argument to Rectangle, the name of a graphics object. >> >> 6.0 tells me that i cannot call Rectangle with 3 arguments. (true, it >> was a bit of a kludge, and in principle i approve of it going away, >> but....) >> >> what is the replacement? >> >> thanks, >> rip >> >

**References**:**Re: v. 6, third argument to rectangle***From:*Jens-Peer Kuska <kuska@informatik.uni-leipzig.de>