Re: Re: v. 6, third argument to rectangle

*To*: mathgroup at smc.vnet.net*Subject*: [mg75890] Re: Re: v. 6, third argument to rectangle*From*: "Drago Ganic" <dganic at vodatel.net>*Date*: Sun, 13 May 2007 05:35:32 -0400 (EDT)*References*: <f21e5e$6e7$1@smc.vnet.net> <200705111030.GAA08108@smc.vnet.net> <f23oii$mvm$1@smc.vnet.net>

Andrzej, thats on purpose because this particular functionality of Rectange is replaced with the new primitive Inset[] . Therefore Rectange[{a, a}, {a, a}, graphics] is obsolete but it still works because of backward compatibility. In new applications, we should use Inset[]. Greetings, Drago "Andrzej Kozlowski" <akoz at mimuw.edu.pl> wrote in message news:f23oii$mvm$1 at smc.vnet.net... > It's true that it works, but the fact that it works seems to be now > undocumented. Mathematica 5.2 documentation states: > > "In Rectangle[{a, a}, {a, a}, graphics], graphics can be any graphics > object." > > but there does not seem to be any such statement in 6.0 (?) > > Andrzej Kozlowski > > > On 11 May 2007, at 19:30, Jens-Peer Kuska wrote: > >> Hi, >> >> that's nonsense -- Rectangle[] work as in the >> versions before with a third argument. >> >> >> Regards >> Jens >> >> rip pelletier wrote: >>> hi, >>> >>> thru 5.2 we could display, for example, 2 graphs side-by-side by >>> using a >>> third argument to Rectangle, the name of a graphics object. >>> >>> 6.0 tells me that i cannot call Rectangle with 3 arguments. (true, it >>> was a bit of a kludge, and in principle i approve of it going away, >>> but....) >>> >>> what is the replacement? >>> >>> thanks, >>> rip >>> >> > >

**References**:**Re: v. 6, third argument to rectangle***From:*Jens-Peer Kuska <kuska@informatik.uni-leipzig.de>