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MathGroup Archive 2007

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Re: Re: v. 6, third argument to rectangle

  • To: mathgroup at smc.vnet.net
  • Subject: [mg75890] Re: Re: v. 6, third argument to rectangle
  • From: "Drago Ganic" <dganic at vodatel.net>
  • Date: Sun, 13 May 2007 05:35:32 -0400 (EDT)
  • References: <f21e5e$6e7$1@smc.vnet.net> <200705111030.GAA08108@smc.vnet.net> <f23oii$mvm$1@smc.vnet.net>

Andrzej,
thats on purpose because this particular functionality of Rectange is 
replaced with the new primitive Inset[] . Therefore Rectange[{a, a}, {a, a}, 
graphics] is obsolete but it still works because of backward compatibility.

In new applications, we should use Inset[].

Greetings,
Drago

"Andrzej Kozlowski" <akoz at mimuw.edu.pl> wrote in message 
news:f23oii$mvm$1 at smc.vnet.net...
> It's true that it works, but the fact that it works seems to be now
> undocumented. Mathematica 5.2 documentation states:
>
> "In Rectangle[{a, a}, {a, a}, graphics], graphics can be any graphics
> object."
>
> but there does not seem to be any such statement in 6.0 (?)
>
> Andrzej Kozlowski
>
>
> On 11 May 2007, at 19:30, Jens-Peer Kuska wrote:
>
>> Hi,
>>
>> that's nonsense  -- Rectangle[] work as in the
>> versions before with a third argument.
>>
>>
>> Regards
>>    Jens
>>
>> rip pelletier wrote:
>>> hi,
>>>
>>> thru 5.2 we could display, for example, 2 graphs side-by-side by
>>> using a
>>> third argument to Rectangle, the name of a graphics object.
>>>
>>> 6.0 tells me that i cannot call Rectangle with 3 arguments. (true, it
>>> was a bit of a kludge, and in principle i approve of it going away,
>>> but....)
>>>
>>> what is the replacement?
>>>
>>> thanks,
>>>    rip
>>>
>>
>
> 




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