Re: How to solve coupled ODEs and PDEs(2ode+2pde) with NDSolve

*To*: mathgroup at smc.vnet.net*Subject*: [mg82998] Re: How to solve coupled ODEs and PDEs(2ode+2pde) with NDSolve*From*: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>*Date*: Tue, 6 Nov 2007 03:47:00 -0500 (EST)*Organization*: Uni Leipzig*References*: <fgk93u$p9c$1@smc.vnet.net>*Reply-to*: kuska at informatik.uni-leipzig.de

Hi, if you have NDSolve[ {f'[t] == t, Derivative[0, 1][u][x, t] == Derivative[2, 0][u][x, t] + f[t], u[x, 0] == x*(1 - x), u[0, t] == 0, u[1, t] == 0, f[0] == 1/2}, {u[x, t], f[x, t]}, {x, 0, 1}, {t, 0, 2}] let simpliy depend f[t] on x too, i.e, f[x,t] and write: NDSolve[ {Derivative[0, 1][f][x, t] == t, Derivative[0, 1][u][x, t] == Derivative[2, 0][u][x, t] + f[x, t], u[x, 0] == x*(1 - x), u[0, t] == 0, u[1, t] == 0, f[x, 0] == 1/2}, {u[x, t], f[x, t]}, {x, 0, 1}, {t, 0, 2}] Regards Jens Santhosh wrote: > hi all > I am relatively new to mathematica. I have 2 odes and 2 pdes. When I tried to > solve them with NDSolve I got following error. > > The length of the derivator operator Derivative[1] in xf'[t] is not same as > number of arguments. > > I know the meaning of error. but in my system xf depends on t only. > any idea from anyone > > thanks in advance > >