       Re: hypergeom

• To: mathgroup at smc.vnet.net
• Subject: [mg81424] Re: hypergeom
• From: dimitris <dimmechan at yahoo.com>
• Date: Sun, 23 Sep 2007 04:28:28 -0400 (EDT)
• References: <fcvqeo\$7g5\$1@smc.vnet.net>

```On 21     , 10:04, Maddy <madd... at gmail.com> wrote:
> Hi,
>
> I got this function
>  HypergeometricPFQ[{1}, {1/2 + k/2, 1 + k/2}, -1/4 t^2 w^2]
>
> How can I write it in normal mathematical equation?
>
> Mathematica help says this:
>
> HypergeometricPFQ[{a1, a2....ap},{b1, b2 ....bq},z] is the generalized hypergeometric function pFq(a;b;z)
>
> I don't get what is p and q in my case?
>
> Kindly help..

Just as a side remark...

Say,

In:=
o = HypergeometricPFQ[{1}, {1/2 + k/2, 1 + k/2}, (-4^(-1))*t^2*w^2]

Out=
HypergeometricPFQ[{1}, {1/2 + k/2, 1 + k/2}, (-(1/4))*t^2*w^2]

Then e.g.

In:=
FullSimplify[FunctionExpand[o /. Thread[{k, t, w} -> {1/2, 1/3, 2}]]]

Out=
(1/2)*Sqrt[3*Pi]*(Cos[2/3]*FresnelC[2/Sqrt[3*Pi]] + FresnelS[2/
Sqrt[3*Pi]]*Sin[2/3])

Cheers
Dimitris

```

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