Re: a question
- To: mathgroup at smc.vnet.net
- Subject: [mg94344] Re: a question
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Wed, 10 Dec 2008 05:11:46 -0500 (EST)
- Organization: Uni Leipzig
- References: <ghnfjh$nlv$1@smc.vnet.net>
- Reply-to: kuska at informatik.uni-leipzig.de
Hi,
Plot[4 x - 6/(3 - 2 x), {x, -5, 5}, Exclusions -> {x == 3/2}]
??
Regards
Jens
alberto gonzalez wrote:
> hi people of mathgroup! i hope youre ok !im alberto from argentina im a mathematica user and=C2 i have a question:
> i tried a lot of ways to plot y=4x-6/3-2x and i cant get to make it noticed in the plot the hole of discontinuity that the sketch presents a when the function turns to P(3/2,-2).the best aproximation ive gotten is
> Plot[((4 x-6)/(3-2 x)),{x,1,2},PlotPloints->2]
> could you help to me please?
> thanks
>