       Re: Distributing square-root (1/2) power through exponential equation

• To: mathgroup at smc.vnet.net
• Subject: [mg101306] Re: Distributing square-root (1/2) power through exponential equation
• From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
• Date: Wed, 1 Jul 2009 06:31:52 -0400 (EDT)
• Organization: Uni Leipzig
• References: <h2cprm\$agj\$1@smc.vnet.net>

```Hi,

Dist = Sqrt[SqD] // PowerExpand

does not what you want ?

Regards
Jens

Steven Matthew Anderson wrote:
> I'm playing with normal distributions, Two random points 1 and 2 with x and y coordinates given by:
>
> px1=PDF[NormalDistribution[Mu,Sx],X1]
> px2=PDF[NormalDistribution[Mu,Sx],X1]
> py1=PDF[NormalDistribution[Mu,Sy],Y1]
> py2=PDF[NormalDistribution[Mu,Sy],Y2]
>
> The square of the Euclidean Distance between them is
>
> SqD = (px2-px1)^2+(py2-py1)^2
>
> Take the square root and expand of that to get
>
> Dist = Sqrt[Expand[SqD]]
>
> Now the question:
>
> How do I get the square root to act just like another power so I can simplify this mess?  I have tried PowerExpand, FullSimplify, Expand, Simplify, and various combinations.  Not sure what I'm missing here.
>

```

• Prev by Date: Re: palettes: Mathematica input
• Next by Date: LogLinearPlot strange "features"
• Previous by thread: Re: Applying lists to FindRoot of a NIntegrate function
• Next by thread: Re: Distributing square-root (1/2) power through exponential equation