MathGroup Archive 2009

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Wrong limit?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg104654] Wrong limit?
  • From: wiso <gtu2003 at alice.it>
  • Date: Fri, 6 Nov 2009 05:14:48 -0500 (EST)

Look at this:

Limit[(x^2 - a^2)/(5 x^2 - 4 a x - a^2), x -> a]
Mathematica answer = 1/3

this is ok for a !=0, but if a = 0 the value is 

Limit[(x^2 - a^2)/(5 x^2 - 4 a x - a^2) /. a -> 0, x -> 0]
1/5


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