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Re: Define a function as a graphics directive?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg105054] Re: [mg105020] Define a function as a graphics directive?
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Thu, 19 Nov 2009 05:23:53 -0500 (EST)
  • Reply-to: hanlonr at cox.net

Show[
 ContourPlot[z Exp[-Sqrt[z^2 + x^2]/2],
  {x, -10, 10}, {z, -10, 0},
  ContourShading -> None,
  Contours -> 7,
  ContourStyle -> {{Red, Thick}}],
 ContourPlot[z Exp[-Sqrt[z^2 + x^2]/2],
  {x, -10, 10}, {z, 0, 10},
  ContourShading -> None,
  Contours -> 7,
  ContourStyle -> {{Black, Thick}}],
 PlotRange -> {{-10, 10}, {-10, 10}}]


Bob Hanlon

---- Porscha Louise McRobbie <pmcrobbi at umich.edu> wrote: 

=============
Hi,

I have a very simple contour plot:


ContourPlot[ z Exp[-Sqrt[z^2 + x^2]/2.], {x, -10, 10}, {z, -10, 10},
  ContourShading -> None, Contours -> 15,
  ContourStyle -> {{Black, Thick}}]


I do not want the plot shaded, but I want to color the contour lines  
according to  a function of z (e.g., Sign[z], where z>0 is black, z<0  
is red). Can this be done within ContourStyle?

I tried putting a function definition for the color inside  
ContourShading, but I get an error since it's not a graphics directive  
(and it's my understanding that ColorFunction is only for shading the  
regions between contours).

Thanks for any input!
Porscha



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