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Re: Re: Permanent Computation Efficiency


Thanks all same!
The community is so nice:)

On Sun, Nov 29, 2009 at 2:39 AM, Leonid Shifrin <lshifr at gmail.com> wrote:

> Hi,
>
> Well, I wouldn't explain it better than Daniel did, and I know far less
> about it than he does. Since Coefficient takes derivatives, it does not need
> to expand the product, but can use the product formula for derivatives -
> this is I guess the reason for its efficiency in this case.
>
> Regards,
> Leonid
>
>
>
>> Could you please tell me what combinatorial knowledge is in need to
>> understand the function Coefficient?
>>
>>
>


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