[Date Index]
[Thread Index]
[Author Index]
Re: ListShadowPlot3D
*To*: mathgroup at smc.vnet.net
*Subject*: [mg103734] Re: [mg103722] ListShadowPlot3D
*From*: Mark McClure <mcmcclur at unca.edu>
*Date*: Sun, 4 Oct 2009 05:36:00 -0400 (EDT)
*References*: <200910031305.JAA06268@smc.vnet.net>
On Sat, Oct 3, 2009 at 9:05 AM, Pasha Karami <karami at geo.uu.nl> wrote:
> I would like to plot 3D and contour plot of a list of data together
> (in one plot) in Mathematica6.
> I know in Mathematica 5.2 with ListShadowPlot3D we could
> plot what i need.
Plot3D and ListPlot3D return their output in the form
Graphics3D[GraphicsComplex[{points, primitives}]]
Thus, you can generate the plots, project the points,
and display it all together. Here's an example:
data = Table[
3 (1 - x)^2 Exp[-x^2 - (y + 1)^2] -
10 (x/5 - x^3 - y^5) Exp[-x^2 - y^2] -
(1/3) Exp[-(x + 1)^2 - y^2] + 20,
{x, -3, 3, 0.5}, {y, -3, 3, 0.5}];
pic = ListPlot3D[data, PlotRange -> All,
InterpolationOrder -> 2, MeshFunctions -> {#3 &},
ColorFunction -> (ColorData["SouthwestColors"][#3] &)];
project[{x_, y_, z_}] = {x, y, 0};
project[list : {{_, _, _} ..}] := project /@ list;
Show[{pic, MapAt[project, pic, {1, 1}]},
PlotRange -> All, ViewPoint -> {2.06082, -2.4884, 1.0054}]
Mark McClure
Prev by Date:
**Re: Using Mathematica with C++**
Next by Date:
**Re: on passing arguments to a function, how to break a list into separate items during a call?**
Previous by thread:
**ListShadowPlot3D**
Next by thread:
**ma-notebooks to nb-notebooks conversion**
| |