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evaluate the floor s to yield a number

  • To: mathgroup at smc.vnet.net
  • Subject: [mg108995] evaluate the floor s to yield a number
  • From: "John Ertle Jr." <ertlejack at sbcglobal.net>
  • Date: Fri, 9 Apr 2010 03:34:08 -0400 (EDT)

In[82]:= J = 
 367*y + floor (7*(y + floor ((m + 9)/12))/4) + int (275*m/9) + da + 
  1721013.5

Out[82]= 2.44254*10^6 + 7/4 floor (1966 + (17 floor)/12) + (2200 int)/
 9

How do you evaluate the floor s in the output in this example to yield a number for the Julian Date.


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