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Re: Binning a dependent variable

  • To: mathgroup at smc.vnet.net
  • Subject: [mg111987] Re: Binning a dependent variable
  • From: Themis Matsoukas <tmatsoukas at me.com>
  • Date: Mon, 23 Aug 2010 02:39:37 -0400 (EDT)

In addition to the solutions posted previously, you may also want to take a look at MovingAverage. If your x points are equidistant and each xi appears only once, then running MovingAverage[yourlist, n] on your list will give you the average x in the interval (xi, xi+(n-1)*deltax), i=1, ..., and the corresponding average of y in that interval:

data = {
   {30, 0.0019},
   {31, 0.0024},
   {32, 0.0026},
   {33, 0.0030},
   {34, 0.0034}
   };
MovingAverage[data, 3]

{{31, 0.0023}, {32, 0.00266667}, {33, 0.003}}

This produces results in overlapping intervals, which you may or may not want.

Themis


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