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Re: How to evaluate the Laplacian of a function as a function?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg114381] Re: How to evaluate the Laplacian of a function as a function?
  • From: Roland Franzius <roland.franzius at uos.de>
  • Date: Thu, 2 Dec 2010 05:42:45 -0500 (EST)
  • References: <id4sma$ci5$1@smc.vnet.net>

Am 01.12.2010 08:15, schrieb Iliyan Georgiev:
> Hi,
>
> I have a stupid problem and cannot find a solution anywhere. I have
> the function
>
> func[x_,y_] := 3/Pi*(1 - x^2 + y^2))^2
>
> which I need the Laplacian of:
>
> funcLapl := Laplacian[func[Xx,Yy]]
>
> The Laplacian is computed correctly, but how can I treat the result as
> a function? I want to be able to evaluate/plot the Laplacian. I tried
> many things and I'm frustrated. My current solution is to manually
> copy the derived Laplacian and create a function from that. It's
> obviously not a good solution.

For expressions, map second derivatives of expression into varaibel 
list, convert the list to a sum and the pair of variable list and body 
into a Function

LaplaceOperator[expr_, x_List]:=
ff[ x, Plus@@ (D[expr,#,#]&/@x))] /. ff->Function

Another way to force evaluation inside a function body during body 
preprocessing is using Evaluate

LaplaceOperator[expr_, x_List] :=
  Function[x, Evaluate[Plus @@ (D[expr, #, #] & /@ x)]]

-- 

Roland Franzius


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