[Date Index]
[Thread Index]
[Author Index]
Replacement rule limitations
*To*: mathgroup at smc.vnet.net
*Subject*: [mg110550] Replacement rule limitations
*From*: "S. B. Gray" <stevebg at ROADRUNNER.COM>
*Date*: Fri, 25 Jun 2010 07:26:47 -0400 (EDT)
*Reply-to*: stevebg at ROADRUNNER.COM
Several responders have told me that replacement rules are the way to
simplify complex expressions and to reduce redundant computations (?).
So let's try an arbitrary expression as a very simple example of
something that could be much more complicated:
exp = 1/Sqrt[
x^2+y^2+z^2] - (x^2+y^2+z^2) + (x^2+y^2+z^2)^(
1/3) /. x^2+y^2+z^2->dd This gives
1/Sqrt[dd] + dd^(1/3)-x^2-y^2-z^2 which is not that useful.
But if I introduce a superfluous multiplier "s":
exp = 1/Sqrt[x^2+y^2+z^2] -
s(x^2+y^2+z^2) + (x^2+y^2+z^2)^(
1/3) /. {x^2+y^2+z^2->dd, s->1} I get
1/Sqrt[dd] + dd^(1/3) - dd which is better. Asking for
exp^2 gives, as desired,
(1/Sqrt[dd] + dd^(1/3) - dd)^2 . But trying to proceed as if this
were regular algebra where cascaded substitutions are routine, I try:
exp/.{x->a^2, y->3b, z->Sqrt[d + e]} , I get the useless result
1/Sqrt[dd] + dd^(1/3) - dd .
Unless I am missing something important (it wouldn't be the first
time!), replacement rules are not a good substitute for real
intermediate variables. This does not even address a feature I'd like to
see in Mathematica in which it would figure out what subexpressions appear
repeatedly and make up its own simplifying intermediate variables. This
could be incorporated into FullSimplify.
Comments will be greatly appreciated.
Steve Gray
Prev by Date:
**Re: ContourStyle Question**
Next by Date:
**Reducible Trinomials How to do quickest algoritm**
Previous by thread:
**Re: Image processing Questions**
Next by thread:
** Re: Replacement rule limitations**
| |