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Re: Remove points from InterpolatingFunction

  • To: mathgroup at smc.vnet.net
  • Subject: [mg109893] Re: Remove points from InterpolatingFunction
  • From: Frank Breitling <fbreitling at aip.de>
  • Date: Fri, 21 May 2010 06:46:43 -0400 (EDT)

Dear Ingo,

Thank you very much for your answer.
Meanwhile I found the solution for your suggested FullForm surgery.
I describe it in my reply to Daniel via this list.

Thanks again for your help.

Frank


On 2010-05-18 07:06, Ingolf Dahl wrote:
> Hi Frank,
> To me it is not completely clear what you are trying to achieve. 
> Either you could remove some of the control points for the definition of the
> interpolation function. Mathematica can give you an interpolation function
> in this case also, in the one-dimensional case. This function can of course
> become very imprecise in the empty interval.
> Or you might want to redefine the function in the unsure interval, and
> replace it by something else. Then you maybe could add some extra control
> points in the small interval? It depends on your problem what is suitable
> and allowed.
> With an already defined InterpolationFunction, you might check the structure
> by looking at the FullForm of it, and make some surgery on that, bur that
> sounds not as the easiest way.
> 
> Best regards
> 
> Ingolf Dahl
> ingolf.dahl at telia.com
> 
> -----Original Message-----
> From: Frank Breitling [mailto:fbreitling at aip.de] 
> Sent: den 17 maj 2010 13:11
> To: mathgroup at smc.vnet.net
> Subject: [mg109778] Remove points from InterpolatingFunction
> 
> Hello,
> 
> I have an interpolating function with a small interval of low accuracy.
> Therefore I would like to remove all points in this interval.
> I already tried to overwrite the interval using Piecewise and Condition
> (/;). However a so defined function causes problems in my later
> calculations due to its higher complexity.
> Therefore I would like to keep the original InterpolatingFuction and
> only remove the problematic points.
> 
> How can I do this?
> 
> Kind regards
> 
> Frank
> 



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