Re: Help with Solve

*To*: mathgroup at smc.vnet.net*Subject*: [mg112383] Re: Help with Solve*From*: Eduardo Cavazos <wayo.cavazos at gmail.com>*Date*: Sat, 11 Sep 2010 05:46:46 -0400 (EDT)*References*: <i6a5i6$kne$1@smc.vnet.net>

On Sep 9, 3:23 am, Eduardo Cavazos <wayo.cava... at gmail.com> wrote: > Here's a couple of equations: > > eq1 = n*Sin[x] == (m*v^2)/r; > eq2 = n*Cos[x] == m*g; > > The goal is to solve for 'x'. > > I can do this in a roundabout way via: > > Solve[eq1 /. Solve[eq2, n], x] I should point out that the answer that I get from using Solve this way is: {{x -> ArcTan[v^2/(g r)]}} which is form the answer I'm looking for. :-) Again, I'm just wondering if Mathematica can do the work for me, instead of having to manually eliminate 'n' in a separate step. Sjoerd and Bob recommended using Reduce. Thanks for the tip! I tried to use Reduce but the results it produced were not in the above form. Ed